Respuesta :

1.<AFC
2.<AFD
3.<AFE
4.<AFB

#5, 6 and 7

m<BAE = 59

m<BAC  +  m<CAD + m<DAE = m<BAE
4x - 20 + x + 12 + x + 1 = 59
6x - 7 = 59
6x = 59 + 7
6x = 66
x = 11

m<BAC = 4x - 20 = 4(11) - 20 = 24
m<CAD = x + 12 = 11 + 12 = 23
m<BAE = x + 1 = 11 + 1 = 12

answer
5.
m<BAC = 24
6.
m<CAD = 23
7.
m<BAE = 12

#8, 9 and 10

m<BAE = 130

m<BAC + m<CAD + m<DAE = m<BAE
3x - 10 + 2x + 5 + x + 15 = 130
6x + 10 = 130
6x = 120
x = 20

m<BAC = 3x - 10 = 3(20) - 10 = 60 -10 = 50
m<CAD = 2x + 5 = 2(20) + 5 = 40 + 5 = 45
m<DAE = x + 5 = 20 + 15 = 35

answer

8.
m<BAC  = 50
9.
m<CAD  = 45
10.
m<DAE = 35