contestada

The area of a circle is 225(pi) in squared. Find the area of the sector whose central angle is 45 degrees.

Respuesta :

take 225(pi) * 45/360 = 28.125(pi) in ^2
the 45 is the measure of the central angle and 360 is the total degrees in a circle

The area of the sector of the circle whose central angle is 45 degrees and the area of circle 225[tex]\pi[/tex] will be 28.125[tex]\pi[/tex] squared.

The area of the circle is given as 225([tex]\pi[/tex] ) and the central angle    [tex]\rm \theta[/tex] is given as 45 degrees.

What is the area of the sector?

The area of the sector of the circle is the space enclosed by the sector, which always originates from the center of the circle.

The area of the sector of the circle = [tex]\rm ( \theta /360 ) \times \pi r^{2}[/tex]

where,      [tex]\rm \theta[/tex] is the angle of sector subtended b the arc at the center, r is the radius of the circle.

So, The area of the sector of the circle = [tex]\rm ( \theta /360 ) \times \pi r^{2}[/tex]

= [tex]\rm ( 45 /360 ) \times 225\pi[/tex]

= [tex]\rm 0.125 \times 225\pi[/tex]

= 28.125[tex]\pi[/tex] squared

Therefore, the area of the sector of the circle whose central angle is 45 degrees and the area of circle 225[tex]\pi[/tex] will be 28.125[tex]\pi[/tex] squared.

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