24 POINTS!!!!!!!!!!!!!!!!!!
The figure is made up of two shapes, a semicircle and a rectangle.

What is the exact perimeter of the figure?

4π+34 in.

8π+72 in.

8π+34 in.

4π+26 in.

24 POINTS The figure is made up of two shapes a semicircle and a rectangle What is the exact perimeter of the figure 4π34 in 8π72 in 8π34 in 4π26 in class=

Respuesta :

9+9+8+4[tex] \pi [/tex]

4π+26 in.

Answer:

[tex](4 \pi+26)\ in[/tex]

Step-by-step explanation:

we know that

The perimeter of the figure is equivalent to the perimeter of a rectangle plus the perimeter of semicircle minus the length side of [tex]8[/tex] inches

step 1

Find the perimeter of rectangle

the perimeter of rectangle is equal to

[tex]P=2(b+h)[/tex]

we have

[tex]b=8\ in[/tex]

[tex]h=9\ in[/tex]

substitute

[tex]P=2(8+9)=34\ in[/tex]

step 2

Find the circumference of semicircle

the of circumference of semicircle is equal to

[tex]C=\frac{1}{2}\pi D[/tex]

we have

[tex]D=8\ in[/tex]

substitute

[tex]C=\frac{1}{2}\pi (8)=4 \pi\ in[/tex]

step 3

Find the perimeter of the figure

[tex]34\ in+4 \pi\ in-8\ in=(4 \pi+26)\ in[/tex]