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In 1995, the average life expectancy in the united states was 75.8 years. the average life expectancy in 2015 was 78.8 years. what is the percentage increase in life expectancy in the last 20 years? choose the closest answer. 3.5%

Respuesta :

taskmasters
First, we determine the difference between the life expectancy in 2015 and 20 years ago. That is,
                                difference = 78.8 - 75.8 = 3 years
Then, we divide this difference by the life expectancy in 1995 and multiply the quotient by 100%. That is,
                   (3/75.8) x 100% = 3.96%
Thus, the increase in life expectancy is approximately 3.96%. 

hamzaahmeds

This question involves the concepts of percentage and ratios.

The percentage increase in life expectancy in the last 20 years is "3.95 %".

What is the Percentage Increase?

The percentage increase in the life expectancy during the last 20 years can be given as the ratio between the increase in life expectancy during last 20 years and the value of life expectancy at the start of 20 years period.

[tex]L = \frac{L(2015)-L(1995)}{L(1995)}*100\%[/tex]

where,

  • L = percentage increase in life expectancy during last 20 years = ?
  • L(2015) = Life expectancy in 2015 = 78.8 years
  • L(1995) = Life expectancy in 1995 = 75.8 years

Therefore,

[tex]L=\frac{98.8\ years-75.8\ years}{75.8\ years}*100\%[/tex]

L = 3.95 %

Learn more about percentage here:

https://brainly.com/question/14979505

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