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A container of gas has a volume of 3.5 L and a pressure of 0.8 atm. Assuming the temperature remains constant, what volume of gas would result if the pressure was 0.5 atm?
A. 5.6 L
B. 2.2 L
C. 0.2 L
D. 1.8 L

Respuesta :

Answer:

The correct answer is option A.

Explanation:

Initial volume of the gas =[tex]V_1=3.5 L[/tex]

Final volume of the gas = [tex]V_2=?[/tex]

Initial pressure of the gas =[tex]P_1=0.8 atm[/tex]

Final volume of the gas = [tex]P_2=0.5 atm[/tex]

Using Boyle's law:

[tex]P_1V_1=P_2V_2[/tex]

[tex]0.8 atm \times 3.5 L=0.5 atm\times V_2[/tex]

[tex]V_2=5.6 L[/tex]

Hence,the correct answer is option A.

Answer : The correct option is, (A) 5.6 L

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

[tex]P\propto \frac{1}{V}[/tex]

or,

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas = 0.8 atm

[tex]P_2[/tex] = final pressure of gas = 0.5 atm

[tex]V_1[/tex] = initial volume of gas = 3.5 L

[tex]V_2[/tex] = final volume of gas = ?

Now put all the given values in the above equation, we get:

[tex]0.8atm\times 3.5L=0.5atm\times V_2[/tex]

[tex]V_2=5.6L[/tex]

Therefore, the final volume of the gas is 5.6 L.