Answer : The pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.
Solution :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 3 atm
[tex]P_2[/tex] = final pressure of gas = ?
[tex]V_1[/tex] = initial volume of gas = 1.40 L
[tex]V_2[/tex] = final volume of gas = 0.950 L
[tex]T_1[/tex] = initial temperature of gas = [tex]35^oC=273+35=308K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]0^oC=273+0=273K[/tex]
Now put all the given values in the above equation, we get the final pressure of gas.
[tex]\frac{3atm\times 1.40L}{308K}=\frac{P_2\times 0.950L}{273K}[/tex]
[tex]P_2=3.918atm[/tex]
Therefore, the pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.
