charlizemarie
contestada

The projectile motion of an object can be modeled using h(t) = gt2 + v0t + h0, where g is the acceleration due to gravity, t is the time since launch, h(t) is the height of the projectile after time t, v0 is the initial velocity, and h0 is the initial height. The acceleration due to gravity is –9.8 m/s2. An object is launched at an initial velocity of 20 meters per second and an initial height of 60 meters. Which solution can be simplified to determine when the object will hit the ground?

Respuesta :

taskmasters

 

The given:

Initial velocity of 20 m/s

Initial height of 60 m

Acceleration due to gravity of -9.8 m/s^2

Original formula:

H(t) = gt2 + v0t + h0

Derivation:

T= gt2 + v0t + h0 / h; where the yielding result will reveal the time when the object will reach the ground.

The solution can be simplified to determine when the object will hit the ground is;

h(t) = -9.8t² + 20t + 60

Projectile motion

We are told that the projectile motion of an object can be modeled using;

h(t) = gt² + v0*t + h0

Where;

g is the acceleration due to gravity

t is the time since launch

h(t) is the height of the projectile after time t

v0 is the initial velocity

h0 is the initial height.

Now, we are given;

  • The acceleration due to gravity; g = –9.8 m/s²
  • Initial velocity; v0 = 20 m/s
  • Initial height; h0 = 60 m

Thus;

h(t) = -9.8t² + 20t + 60

Read more on projectile motion at; https://brainly.com/question/14899130

Otras preguntas