A 10.0-g bullet moving at 300 m/s is fired into a 1.00-kg block at rest. the bullet emerges (the bullet does not get embedded in the block with half of its original speed. what is the velocity of the block right after the collision?

Respuesta :

Momentum before the hit:
p = mv = 0.01 * 300 + 1 * 0 

Momentum after the hit:
p = 0.01 * 150 + 1 * v

Momentum is conserved:
0.01 * 300 = 0.01 * 150 + v 
3 = 1.5 + v
v = 1.5

The velocity of the block after the collision is 1.5 m/s.

The velocity of the block right after the collision is 1.5 m/s.

Momentum before the hit:

p = mv = 0.01 * 300 + 1 * 0

Momentum after the hit:

p = 0.01 * 150 + 1 * v

Momentum is conserved:

0.01 * 300 = 0.01 * a 100 and 50 + v

3 = 1.5 + v

v = 1.5

the rate of the block after the collision is 1.5 m/s.

How do you describe a collision?

Collision, additionally known as impact, in physics, the unexpected, forceful coming together in direct contact of our bodies, which include, for instance, two billiard balls, a golfing club, and a ball, a hammer and a nail head, railroad cars whilst being coupled together, or a falling object and a floor.

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