Respuesta :
The formula for the area of a parallelogram is
A=b*h where b=base and h=height
if the base were to increase by 3times and the height were to increase by 2 times then
6A=b*h
The area of the parallelogram would be 6 times larger
So if the original area was 47units², then the new area would be
47*6=282units²
Answer=282units²
A=b*h where b=base and h=height
if the base were to increase by 3times and the height were to increase by 2 times then
6A=b*h
The area of the parallelogram would be 6 times larger
So if the original area was 47units², then the new area would be
47*6=282units²
Answer=282units²
The area of the new parallelogram for the given condition is evaluated being of 282 sq. units.
How to find the area of a parallelogram whose height and base length are given?
Suppose the considered parallelogram has:
- height = h units
- length of base = b units.
Then, we get:
[tex]A = b \times h \: \rm unit^2[/tex] (as area of the parallelogram).
For this case, we are specified that:
The old parallelogram had base of y units and height of x units.
Its area was 47 sq. units.
That means:
[tex]A = xy = 47[/tex]
Now, new parallelogram has base of 3y units and height of 2x units.
Its area would be:
[tex]A = 3x \times 2y = 6xy = 6 \times xy = 6 \times 47 = 282 \: \rm unit^2[/tex] (because we had [tex]xy = 47[/tex])
(sign of multiplication is often hidden if there are non numeric symbols and numbers being multiplied are written together. Thus, [tex]xy = x \times y[/tex])
Thus, the area of the new parallelogram for the given condition is evaluated being of 282 sq. units.
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