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In a batch of 890 calculators, 12 were found to be defective. What is the probability that a calculator chosen at random will be defective? Write the probability as a percent. Round to the nearest tenth of a percent if necessary.

A.74%

B.1.3%

C.98.7%

D.1.8%

Respuesta :

Equanimity
12/890 are defective. x/100 are defective.
Multiply 12 by 100 and 890 by x.
1200/890x.
1200/890=1.34
There is a 1.3% chance.
Your answer is B.)
JeanaShupp

Answer: 1.3%

Step-by-step explanation:

Given: The number of calculators T= 890

The number of defective calculators D= 12

Now, the probability that a calculator chosen at random will be defective is given by :-

P(defective )[tex]=\dfrac{D}{T}[/tex]

⇒P(defective )[tex]=\dfrac{12}{890}=0.0134831460674[/tex]

In percent, P(defective )[tex]=0.0134831460674\times100=1.34831460674\%=1.3%[/tex]

Hence, the probability that a calculator chosen at random will be defective = 1.3%

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