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A line passes through (–7, –5) and (–5, 4).Write an equation for the line in point-slope form. Rewrite the equation in standard form using integers.
A) y + 5 = 9/2x – 7); –9x + 2y = 53
B) y + 5 = 9/2(x + 7); –9x + 2y = 53
C) y – 5 = 9/2(x + 7); –9x + 2y = –53
D)y + 7 = 9/2(x + 5); –9x + 2y = 31

Respuesta :

mcminnlaiton2022

B) y+5=9/2(x+7);-9x+2y=53

Answer:

Option B is correct.

Step-by-step explanation:

We have been given the points (-7,-5) and (-5,4)

We have an equation for point-slope form:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}\cdot (x-x_1)[/tex]

Here,[tex]x_1=-7,y_1=-5,x_2=-5,y_2=4[/tex]

On substituting the values in the formula:

[tex]y-(-5)=\frac{4-(-5)}{-5-(-7)}\cdot (x-(-7))[/tex]

[tex]\Rightarrow y+5=\frac{9}{2}\cdot (x+7)[/tex]

[tex]\Rightarrow 2y+10= 9\cdot (x+7)[/tex]

[tex]\Rightarrow -9x+2y=53[/tex]

Therefore, Option B is correct.

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