Answer:
[tex]2\times 10^{-12}[/tex]
Step-by-step explanation:
We are given that two numbers are
[tex]2.3\times 10^{-4}[/tex] and [tex]1.15\times 10^8[/tex]
We have to find that how many times greater [tex]2.3\times 10^{-4}[/tex] than [tex]1.15\times 10^8[/tex] approximately.
In order to find that we divide [tex]2.3\times 10^{-4}[/tex] by [tex]1.15\times 10^8[/tex]
[tex]\frac{2.3\times 10^{-4}}{1.15\times 10^8}[/tex]
[tex]\frac{2.3\times 10^{-4}}{1.15\times 10^8}={230\times 10^{-4-8}[/tex]
[tex]\frac{2.3\times 10^{-4}}{1.15\times 10^8}=2\times 10^{-12}[/tex]
[tex]2.3\times 10^{-4}=2\times 10^{-12} [/tex] times [tex]1.15\times 10^8[/tex]
Hence,[tex]2.3\times 10^{-4}[/tex] is [tex]2\times 10^{-12}[/tex] times greater than [tex]1.15\times 10^8[/tex]
