The distance of the 5kg book from the floor if it possesses 196J of potential energy is 4m.
Given the data in the question;
- Potential energy of the book, [tex]P.E = 196J[/tex]
- Mass of the book; [tex]m = 5kg[/tex]
- Distance of book from floor; [tex]h = ?[/tex]
- Acceleration due to gravity; [tex]g = 9.8m/s^2[/tex]
Potential Energy is referred to as stored energy, it an energy possessed by a body based on its relative position of the components of that system.
Its is calculated using the following formula:
[tex]P.E = mgh[/tex]
where m is the mass of the object, g is the earth's gravity and h is the distance or height
Now, we substitute our given values into the equation and 'h
[tex]196J = 5kg\ *\ 9.8m/s^2\ *\ h[/tex]
we know that; 1 Joule = 1 Newton meter and 1 Newton = 1 kg⋅m/s²
Hence
[tex]196 kgm^2/s^2 = 5kg \ * 9.8m/s^2\ * \ h\\\\196 kgm^2/s^2 = 49kgm/s^2\ * \ h\\\\h = \frac{196 kgm^2/s^2}{49kgm/s^2}\\\\h = 4 m[/tex]
Therefore, the distance of the 5kg book from the floor if it possesses 196J of potential energy is 4m.
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