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Let set A = {odd numbers between 0 and 100} and set B = {numbers between 50 and 150 that are evenly divisible by 5}.

What is A ∩ B?


{50, 55, 60, 65, 70, 75, 70, 85, 90, 95}
{55, 65, 75, 85, 95}
{all odd numbers between 1 and 99}
{numbers between 1 and 150 that are evenly divisible by 5}

Respuesta :

JeanaShupp

Answer: {55, 65, 75, 85, 95}


Step-by-step explanation:

Given: A = {odd numbers between 0 and 100}

B= {numbers between 50 and 150 that are evenly divisible by 5}

Thus, A={1,2,3,4,5,6,7,8,.......99}

and B={55,60,65,70,75,80,85,90,95......145}

The notation A ∩ B means A intersection B which is the set of elements that are common in set A and in set B.

Now, [tex]A\bigcap B=\left \{ 55,65,75,85,95 \right \}[/tex]


MrRoyal

The elements of set A ∩ B are  {55, 65, 75, 85, 95}

The sets are given as:

A = {odd numbers between 0 and 100}

B= {numbers between 50 and 150 that are evenly divisible by 5}

The above means that:

A = {1,2,3,4,5,6,7,8,.......99}

B = {55,60,65,70,75,80,85,90,95......145}

To calculate set A ∩ B, we list the common elements in both sets, without repetition.

So, we have:

A ∩ B =  {55, 65, 75, 85, 95}

Hence, the elements of set A ∩ B are  {55, 65, 75, 85, 95}

Read more about sets at:

https://brainly.com/question/2099071

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