contestada

Suppose a new car that costs $25,000 depreciates by 12% each year. In about how many years will the car be worth $15,000? Use the equation 15,000 = (25,000)(0.88)x and round the value of x to the nearest year

Respuesta :

Aliwohaish12
X=log(15,000÷25,000)÷log(0.88)
x=3.9=4years

Answer:

4 years.

Step-by-step explanation:

Given : A new car that costs $25,000 depreciates by 12% each year.

To Find:  In about how many years will the car be worth $15,000?

Solution:

Principal = $25000

Rate of decrease = 12%

Amount = $15000

Equation:[tex]15,000 = (25,000)(0.88)^x[/tex]

x will give the years in after which car value will be $15000

So, [tex]15,000 = (25,000)(0.88)^x[/tex]

[tex]\frac{15000}{25000}=(0.88)^x[/tex]

[tex]0.6=(0.88)^x[/tex]

[tex]3.99603=x[/tex]

Thus in about 4 years car value will be $15,000.

Otras preguntas