Answer: The required equation of the line is [tex]5y=x.[/tex]
Step-by-step explanation: We are given to find the equation of the line passing through the points (0, 0) and (15, 3).
We know that
the equation of a line passing through two points (a, b) and (c, d) is given by
[tex]y-b=\dfrac{d-b}{c-a}(x-a).[/tex]
Therefore, the equation of the line passing through the points (0, 0) and (15, 3) is given by
[tex]y-0=\dfrac{3-0}{15-0}(x-0)\\\\\\\Rightarrow y=\dfrac{3}{15}x\\\\\\\Rightarrow y=\dfrac{1}{5}x\\\\.\Rightarrow 5y=x.[/tex]
Thus, the required equation of the line is [tex]5y=x.[/tex]
