Respuesta :

skyluke89

The correct answer is:

decreases.

In fact, the electrical force between two charged particles is given by

[tex] F=k \frac{q_1 q_2}{r^2} [/tex]

where k is the Coulomb's constant, q1 and q2 are the charges of the two particles, and r is their separation. From the equation, we see that if the distance r increases, the magnitude of the force (F) decreases.

Answer:

Decreases

Explanation:

The electric force between two charged particle is given by :

[tex]F=k\dfrac{q_1q_2}{d^2}[/tex]........(1)

Where

k is the electrostatic constant

[tex]q_1\ and\ q_2[/tex] are charged particle

d is the distance between charges

We can see from equation (1) that the electrical force of attraction is inversely proportional to the square of the distance between them. So, as the distance increases, the electrical forces of attraction between oppositely charged particles decreases.

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