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if the pressure exerted by a gas at 27.0 c in a vessel of volume 0.050 L is 4.00 atm, how many moles of the gas are pressure?

Respuesta :

Edufirst
This is a problem to apply the ideal gas equation.

pV = n RT => n = pV / RT

Where:

R is the Universal constant of gases = 0.082 atm*liter / K*mol

p = 4.00 atm
V = 0.050 liter
T = 27.0 + 273.15 = 300.15 K

n = pV / RT = 4.00 atm * 0.050 liter / (0.082 atm*liter/K*mol * 300.15K) = 0.0081 mol

Answer: 0.0081 mol

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