Assuming a fair coin and a fair 6-sided die.
Coin has 2 sides with equal probability, 50% each.
Die has 6 sides with equal probability, 1/6 odds for each side.
Odds of heads = 1/2.
Odds of die rolling 5 or greater (5 or 6) = 2/6.
The probability of both things happening is the multiplication of the probability of the two happening separately, or (1/2)*(2/6) = 1/6.
Answer: The required probability is 25%.
Step-by-step explanation: Given that a coin is flipped and a number cube is rolled.
We are to find the probability of getting a tail on the coin and an even number on the number cube.
The sample space for flipping a coin and rolling a number cube is given by
S = {H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6}
⇒ n(S) = 12.
Let A denote the event of getting tail and an even number.
Then, A = {T2, T4, T6}
⇒ n(A) = 3.
Therefore, the probability of event A is given by
[tex]P(A)=\dfrac{n(A)}{n(S)}=\dfrac{3}{12}=\dfrac{1}{4}\times 100\%=25\%.[/tex]
Thus, the required probability is 25%.
