A certain class of 160 students has 40 honor students and 60 athletes. Eighty students in the class do not participate in sports and are not honor students. If a student is selected at random to represent the class, what is the probability that he is both an honor student and an athlete?

Respuesta :

Since we have 80 students in the class do not participate in sports and are not honor student, we have this solution:
160 - 80 = 80 students remaining who are honors and athletes

Since we have 40 honor students and 60 are athletes, we have this solution:
40 + 60 -80 = 20

The probability is shown below:
20 / 160 = 1 / 8.

The answer is 1/8.

Answer:

1/8 is the answer

Explanation: