Answer:
T' = T / sqrt 2
Explanation:
According to the formula of time period of a loaded spring
[tex]T = 2\pi \sqrt{\frac{m}{k}}[/tex] .... (1)
where, m is the mass on the spring and k be the spring constant.
Here we observe that the time period is inversely proportional to the square root of the spring constant.
If the spring constant is doubled then the time period is
[tex]T' = 2\pi \sqrt{\frac{m}{2k}}[/tex] ....(2)
Dividing equation (2) by equation (1), we get
T' = T / sqrt 2
