Respuesta :

Acceleration is 3 f/ts
you subtract then divide 
(45-60)/5

Answer:

[tex]3\ ft/s^2.[/tex]

Explanation:

It is given that initial speed of car, [tex]v_i=45\ ft/s.[/tex]

Also, final speed of car, [tex]v_f=60\ ft/s.[/tex]

Time taken by the car during this process, [tex]t=5\ s.[/tex]

We need to find the acceleration of car, a.

Now, by newton's equation of motion.

We know, [tex]v_f-v_i=a\times t[/tex]

Putting all required values in above equation.

[tex]60-45=5\times a.\\a=3\ ft/s^2.[/tex]

Therefore, the acceleration by the car during this process is [tex]3\ ft/s^2.[/tex]

Hence, it is the required solution.