Answer:
[tex]x=\frac{5+\sqrt{65}}{-4} [/tex]and [tex]x=\frac{5-\sqrt{65}}{-4}[/tex]
Step-by-step explanation:
We are given that an equation
[tex]-2x^2-5x+5=0[/tex]
We have to solve the equation using by quadratic formula
[tex]ax^2+bx+c=0[/tex]
[tex]x=\frac{-b\pm\sqrt{D}}{2a}[/tex]
[tex]D=b^2-4ac[/tex]
We have a=-2,b=-5 and c=5
[tex]D=(-5)^2-4\times (-2)\times 5=25+40=65[/tex]
[tex]x=\frac{-(-5)\pm\sqrt{65}}{2(-2)}[/tex]
[tex]x=\frac{5+\sqrt{65}}{-4} [/tex]and [tex]x=\frac{5-\sqrt{65}}{-4}[/tex]
