Two planes make a 1500 mile flight, one flying 25 miles per hour faster than the other. The quicker plane makes the trip 3 hours faster. How long did it take the slower plane to complete the flight?

Respuesta :

1500/25=60
60-3=57
It took 57 hours for the slower plane to complete the flight, and it was flying at 19mph. My question is, how did a plane stay in the sky going only 25 miles per hour? Let alone even 19 miles per hour? I can pedal a bicycle faster than that!

Slower plane will take 15 hours time to complete the flight of 1500miles distance .

What is speed?

" Speed is defined as the total distance travelled per unit time."

Formula used

Speed = (total Distance travelled) / (time taken )

According to the question,

Distance travelled = 1500 miles

'x' represents the speed of the slower plane

'h' represents the time taken to complete the trip by slower plane

Therefore,

'x + 25'  represents the speed of the faster plane

'h-3' represents the time taken to complete the trip by faster plane

Substitute the value in the formula for slower and faster plane we get,

Faster plane : [tex]x +25 = \frac{1500}{h-3}[/tex]                   ____(1)

Slower plane :  [tex]x= \frac{1500}{h}[/tex]                         _____(2)

Substitute the value of 'x' from (2) in (1) we get,

   [tex]\frac{1500}{h} +25 = \frac{1500}{h-3}[/tex]

⇒[tex]25 = \frac{1500}{h-3}-\frac{1500}{h}[/tex]

⇒[tex]25 =1500( \frac{1}{h-3}-\frac{1}{h})[/tex]

⇒[tex]1 =60( \frac{h-h+3}{(h)(h-3)} )[/tex]

⇒[tex]1=(60)\frac{3}{h^{2} -3h}[/tex]

⇒[tex]h^{2} -3h -180=0[/tex]

⇒[tex]h^{2} -15h+12h -180=0[/tex]

⇒[tex](h-15)(h+12)=0[/tex]

⇒ [tex]h=15 or h=-12[/tex]

Time cannot be negative.

Hence, time taken by slower plane to complete the trip is equals to

h = 15hours.

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