Respuesta :

[tex]\bf \qquad \textit{Continuously Compounded Interest Earned Amount}\\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\to &\$15000\\ P=\textit{original amount}\\ r=rate\to 5.9\%\to \frac{5.9}{100}\to &0.059\\ t=years\to &12 \end{cases} \\\\\\ 15000=Pe^{0.059\cdot 12}[/tex]

solve for P

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