let's calculate the volume of the aluminum foil using the density
[tex]density= \frac{mass}{volume} -----\ \textgreater \ volume= \frac{mass}{density} [/tex]
[tex]volume= \frac{7.291 grams}{2.700 g/cm^3} =[/tex] [tex]2.700 cm^3[/tex]
let's recall the volume of a rectangle formula
[tex]Rectangle_{volume}= [/tex] height x wide x long
we already have long and wide, and volume. so let's solve for the unknown
[tex]2.700 cm^3= heightx 25.70 cm x 28.32 cm[/tex]
[tex]height= \frac{2.700}{25.70 x 29.32} = 0.003710 cm[/tex]
