Answer:
[tex](-\sqrt{3},1)[/tex]
Step-by-step explanation:
The angle given to us is -210° . Let us find the slope of the terminal side of this angle.
As the angles measures -210° in clockwise direction from x axis, it measures 360°-210°=150° in anti clockwise direction from x axis.
Hence the slope of the terminal side will be
tan 150° = tan (180°-30°) = tan (-30°) = -tan 30°
tan 150° = [tex]-\frac{1}{\sqrt{3}}[/tex]
now we see the slope. Now we have to determine one point on this terminal side. We already have (0,0) on it.
We use the formula for slope in order to do so..
slope
[tex]-\frac{1}{\sqrt{3}}= \frac{y-0}{x-0}[/tex]
[tex]-\frac{1}{\sqrt{3}}= \frac{y}{x}[/tex]
Hence we can say that
[tex](-\sqrt{3},1)[/tex]
can a point on the terminal side of -210°
