Answer:
[tex]\frac{\pi}{2}[/tex]
Step-by-step explanation:
We are given that a function
[tex]y=3 sin(4t)[/tex]
We have to find the period t of the given function.
To find the period of given function we will compare with general sine function equation period.
[tex]f(x) =A sin(Bx+C)+D[/tex]
Period=[tex]\frac{2\pi}{\mid B\mid}[/tex]
By comparing we get
[tex]\mid B\mid=4[/tex]
Substitute the value in the given formula to finding the period
Then ,we get the period t of given function=[tex]\frac{2\pi}{4}=\frac{\pi}{2}[/tex]
Hence, the period of given function =[tex]\frac{\pi}{2}[/tex]
