Here is how I completed the problem:
I started by creating a ratio:
[tex] \frac{x}{0.18} + \frac{360}{0.10} = \frac{x+360}{0.15}[/tex]
Where 'x' is the desired amount of the 18% solution of sulfuric acid.
From here, I solved for 'x':
[tex] \frac{0.10x}{0.018} + \frac{360(0.18)}{0.018} = \frac{x+360}{0.15} [/tex]
[tex] \frac{0.10x}{0.018} + \frac{64.8}{0.018} = \frac{x+360}{0.15} [/tex]
[tex] \frac{0.10x+64.8}{0.018} = \frac{x+360}{0.15} [/tex]
[tex]0.15(0.10x+64.8) = 0.018(x+360)[/tex]
[tex]0.015x+9.72 = 0.018x+6.48[/tex]
[tex]0.003x = 3.24[/tex]
[tex]x = 1080[/tex]
∴You will need to add 1080ml of 18% Sulfuric Acid in order to obtain a 15% solution.
