Respuesta :
Answer:
Hence, the probability of Tim Duncan making all of his next 8 free throw attempts is:
[tex](\dfrac{18}{25})^8=0.0722204136[/tex]
Step-by-step explanation:
As the probability of one free throw does not depend on the any other i.e. the probability of each throw is independent.
Hence, the probability of making all of his next 8 free throw is calculated as:
Probability of next 8 free throw=Probability of first free throw×probability o f second free throw×··················× Probability of 8th free throw.
i.e. it is given by:
[tex]Probability=\dfrac{72}{100}\times \dfrac{72}{100}\times \dfrac{72}{100}\times \dfrac{72}{100}\times \dfrac{72}{100}\times \dfrac{72}{100}\times \dfrac{72}{100}\times \dfrac{72}{100}\\\\\\Probability=(\dfrac{72}{100})^8\\\\Probability=(\dfrac{18}{25})^8[/tex]
Hence, the probability is:
[tex](\dfrac{18}{25})^8=0.0722204136[/tex]
We have that the he probability of Tim Duncan making all of his next 8 free throw attempts is mathematically given as
[tex]P=0.72^8[/tex]
From the question we are told
- Tim Duncan is shooting free throws.
- Making or missing free throws doesn't change the probability that
- he will make his next one, and he makes his free throws 72% of the time.
- What is the probability of Tim Duncan making all of his next 8 free throw attempts?
Arithmetic
Generally the equation for the binomial probability is mathematically given as
[tex]P=\frac{n!}{X!(n-X)!}*p^X*(1-p)^{n-X}\\\\Therefore\\\\ P=\frac{8!}{8!(8-8)!}*0.72^8*(1-0.72)^{0}[/tex]
[tex]P=0.72^8[/tex]
For more information on Arithmetic visit
https://brainly.com/question/22568180
