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Vincent is giving cakes to some children at a carnival. He has 2 strawberry cakes, 6 pineapple cakes, and 7 chocolate cakes. If Vincent selects a cake randomly without looking, what is the probability that he will give a pineapple cake to the first child and then a strawberry cake to the second child? (5 points)


6 over 15 multiplied by 2 over 14 is equal to 12 over 210

6 over 15 plus 2 over 14 is equal to 114 over 210

6 over 15 multiplied by 2 over 15 is equal to 12 over 225

6 over 15 plus 2 over 15 is equal to 8 over 15

Respuesta :

musiclover10045

2+6+7 = 15 total cakes

6 pineapple so probability is 6/15

 then there would be 14 cakes

2 strawberry for a probability of 2/14

6/15 x 2/14 = 12/210

 the first answer is the right one

Answer:

[tex]\frac{12}{210}[/tex]

Step-by-step explanation:

Strawberry cakes = 2

Pineapple cakes = 6

Chocolate cakes = 7

Total cakes = 15

Now we are given that  Vincent selects a cake randomly without looking, and he will give a pineapple cake to the first child

So, probability of getting a pine apple cake in first draw = [tex]\frac{\text{No. of pineapple cakes}}{\text{Total no. of cakes}}[/tex]

                                                                                             = [tex]\frac{6}{15}[/tex]

Now total no. of remaining cakes = 15-1 =14

Now we are given that  Vincent selects a cake randomly without looking, and he will give a strawberry cake to the second child

So, So, probability of getting a strawberry cake in second draw= [tex]\frac{2}{14}[/tex]

So,  the probability that he will give a pineapple cake to the first child and then a strawberry cake to the second child =  [tex]\frac{6}{15} \times\frac{2}{14} [/tex]

                                                                           =  [tex]\frac{12}{210}[/tex]

Hence Option A is true.

The probability that he will give a pineapple cake to the first child and then a strawberry cake to the second child is [tex]\frac{12}{210}[/tex]

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