logannyehoskins
contestada

The point-slope form of the equation of the line that passes through (–9, –2) and (1, 3) is y – 3 = 1/2 (x – 1). What is the slope-intercept form of the equation for this line?

Respuesta :

Luv2Teach
You just have to simplify that point-slope equation in order to get it into slope-intercept:
[tex]y-3= \frac{1}{2} (x-1)[/tex]
[tex]y-3= \frac{1}{2}x- \frac{1}{2} [/tex]
[tex]y= \frac{1}{2} x- \frac{1}{2} +3[/tex]
[tex]y= \frac{1}{2} x- \frac{1}{2} + \frac{6}{2} [/tex]
[tex]y= \frac{1}{2} x+ \frac{5}{2} [/tex]

Answer:

[tex]y=\frac{x}{2}+\frac{5}{2}[/tex]

Step-by-step explanation:

Hello

thanks for asking this question, I think I can help you with this

if you have the point-slope form of the equation of a line, just isolate "y" to find the slope-intercept form

Step 1

[tex]y-3=\frac{1}{2} (x-1)\\\\y-3=\frac{x}{2}-\frac{1}{2} \\Add\ 3\ in\ both sides\\\\y-3+3=\frac{x}{2}-\frac{1}{2} +3\\y=\frac{x}{2}-\frac{1}{2}+3\\y=\frac{x}{2}+\frac{5}{2}[/tex]

so the answer is

[tex]y=\frac{x}{2}+\frac{5}{2}[/tex]

where 1/2 is the slope, and 5/2 is the intercept with y-axis

I really hope it helps , Have a great day.

Otras preguntas