Answer:
The answer is the option C
[tex]V=38.37\ ft/sec[/tex]
Step-by-step explanation:
we have that
[tex]V=\sqrt{64h}[/tex]
In this problem we have
[tex]h=23\ ft[/tex]
Substitute in the formula and solve for V
[tex]V=\sqrt{64(23)}[/tex]
[tex]V=\sqrt{1,472}\ ft/sec[/tex]
[tex]V=38.37\ ft/sec[/tex]