Answer:
Given the functions: [tex]f(x)= -x^2 +3x+5[/tex] and [tex]g(x) = x^2+2x[/tex]
Now, calculate first [tex](f+g)(x)[/tex] ;
[tex](f+g)(x) = f(x) + g(x)[/tex]
Substitute the given values we have;
[tex](f+g)(x) = -x^2+3x+5+x^2+2x[/tex]
Combine like terms;
[tex](f+g)(x) =5x+5[/tex]
Let y = [tex](f+g)(x)[/tex]
Then, we have y = 5x+5
Now, Graph the equation of the line y =5x +5
Using slope intercept form: An equation of line is given by :
y = mx +b ; where m is the slope of the line and b is the y-intercept.
On comparing we get;
m = 5 (Since, slope is positive which means a line moves upward on a graph from left to right)
Now, find the intercepts of the equation: y=5x+5;
x-intercepts: The graph or line crosses the x-axis i.,e
Substitute y = 0 and solve for x;
0 = 5x +5
Subtract 5 on both sides we get;
-5 = 5x
Divide both sides by 5 we get;
x = -1
x-intercepts= = (-1, 0)
Similarly for y-intercept:
Substitute the value of x= 0 and solve for y;
y = 5(0)+5
y = 5
y-intercepts = (0, 5)
Now, using these point we can draw a graph of function [tex](f+g)(x) =5x+5[/tex] as shown below in the attachment.
