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A railroad flatcar is traveling to the right at a speed of 13.0 m/s relative to an observer standing on the ground. someone is riding a motor scooteron the flatcar. what is the velocity (magnitude and direction) of the scooter relative to the flatcar if the scooterâs velocity relative to the observer on the ground is

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BlueSky06
Given:

[tex]v \frac{x}{y} \frac {t} {0} = 13 \frac{m} {s} [/tex]

[tex]v \frac{0} {g} = 0 \frac{m} s} [/tex]

SOLUTION:

(a) 

[tex]v \frac{s} {t} = ? for v \frac{s} {0} = +18 \frac{m} {s} [/tex]

[tex]v \frac {s} {t} = v \frac {s} {0} + v \frac {0} {T} = +18 \frac {m} {s} + (-13 \frac {m} {s} )[/tex]

[tex]v \frac {s} {t} = +5 \frac {m} {s} [/tex]

(b) 

[tex]v \frac {s} {t} = ? for \frac {s} {0} = -3.0 \frac {m} {s} [/tex]

[tex]v \frac {s} {t} = v \frac {s} {0} + v \frac {0} {t} = -3.0 \frac {m} {s} + (-13 \frac {m} {s} ) = -16 \frac {m} {s} [/tex]

(c)

[tex]v \frac {s} {t} = ? for \frac {s} {0} = 0 \frac {m} {s} [/tex]

[tex]v \frac {s} {t} = v \frac {s} {0} + v \frac {0} {t} = 0 \frac {m} {s} + (-13 \frac {m} {s} ) = -13 \frac {m} {s} [/tex]

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