Answer:
y = -x/6 + 5.
Step-by-step explanation:
We can use the point-slope form of linear equations to find the equation of the perpendicular line that passes through (-6, 4):
y - y1 = m(x - x1)
where:
m is the slope (-1/6 in this case)
(x1, y1) is the point the line passes through (-6, 4)
Plugging in the values:
y - 4 = (-1/6)(x - (-6))
Simplifying the right side:
y - 4 = (-1/6)x + 1
Combining like terms:
y = (-1/6)x + 5
Therefore, the equation of the line that is perpendicular to y = 6x + 3 and passes through (-6,4) is y = -x/6 + 5.
Answer:
Step-by-step explanation:
perp. -1/6
y - 4 = -1/6(x + 6)
y - 4 = -1/6x - 1
y = -1/6x + 3
