To solve the equation √(y^4 + 2y^2 + 1) = y^2 + 1, we can start by squaring both sides of the equation to eliminate the square root.
(√(y^4 + 2y^2 + 1))^2 = (y^2 + 1)^2
Simplifying both sides:
y^4 + 2y^2 + 1 = y^4 + 2y^2 + 1
We can see that the equation simplifies to 0 = 0. This means that the equation is an identity, and it is true for all values of y.
Therefore, the solution to the equation is y ∈ R (all real numbers).
