Step-by-step explanation:
To find the value of x that makes the statement true: \frac{2}{7}x^{3}-x^{3}+3=2 , we can start by simplifying the equation. Combining like terms, we have: \frac{\sigma}{7}x^{3}-x^{3}=-1. . To combine the terms on the left-hand side, we need to find a common denominator. In this case, the common denominator is 7. So, we have: \frac{3x^{3}}{7}-\frac{7x^{3}}{7}=-1. Simplifying further, we get: \frac{3x^{3}-7x^{3}}{7}=-1 rewritten as: . This can be \frac{-4x^{3}}{7}=-1 To solve for x, we can multiply both sides of the equation Doing so, we get by- :x^{3}=\frac{l}{4}. 7 TA To find the value of x, we can take the cube root of both sides of the equation. Taking cube root 7 of, we find: x=\sqrt[3]{\frac{7}{4}}. Therefore, the value of x that makes the statement true is x=\sqrt[3]{\frac{7}{4}}.
