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The amount y (in grams) of the radioactive isotope chromium-51 remaining after t days is y=a(0.5)^t/28, where a is the initial amount (in grams). What percent of the chromium-51 decays each day?

The amount y in grams of the radioactive isotope chromium51 remaining after t days is ya05t28 where a is the initial amount in grams What percent of the chromiu class=

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1frogaroni

Answer:

50% of the chromium-51 decays each day.

Step-by-step explanation:

The percentage of chromium-51 that decays each day can be found by considering the decay factor, which is [tex]\frac{1}{2}[/tex] or 0.5. To express this as a percentage, subtract the decay factor from 1 and then multiply by 100:

Decay percentage= (1 - decay factor) X 100

Decay percentage= (1 - 0.5) X 100 = 0.5 X 100 = 50%

Therefore, 50% of the chromium-51 decays each day.

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