Respuesta :

icetornato
To find the equation of the line passing through the given points (0, -3) and (3, 3), we can use the point-slope form of the equation of a line:

y - y1 = m(x - x1)

where m is the slope of the line and (x1, y1) is any point on the line.

First, let's find the slope (m) using the formula:

m = (y2 - y1) / (x2 - x1)

Given points: (x1, y1) = (0, -3) and (x2, y2) = (3, 3)

m = (3 - (-3)) / (3 - 0) = 6 / 3 = 2

Now that we have the slope, let's choose one of the points, for example, (0, -3), and substitute the values into the point-slope form:

y - (-3) = 2(x - 0)

y + 3 = 2x

Now, let's simplify the equation:

y + 3 = 2x
y = 2x - 3

So, the equation of the line passing through the points (0, -3) and (3, 3) is y = 2x - 3.
gracebeauchamp

Answer:

y=2x-3

Step-by-step explanation:

Write this by using point slope form which says

(y-y₁)=m(x-x₁). The first step is to find the slope. To do this, you need to take the rise over the run, the change in y over change in x or whatever you call it. The formula for this is [tex]\frac{y2-y1}{x2-x1}[/tex]=m

3-(-3)/3-0 = 6/3 = 2  so m=2

Now pick one of the two points. Personally, I would choose (0,-3) because of the zero but it really doesn't matter.

y+3=2(x-0) or y=2x-3

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