A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.




y=−16x ^2 + 174x+67

Respuesta :

Answer:

To find the time that the rocket will hit the ground, we need to determine when the height of the rocket, y, becomes zero. The given equation for the height of the rocket is y = -16x^2 + 153x + 98. This is a quadratic equation that can be solved to find the values of x when y is zero.

Step-by-step explanation:

To find the time that the rocket will hit the ground, we need to determine when the height of the rocket, y, becomes zero. The given equation for the height of the rocket is y = -16x^2 + 153x + 98. Setting y to zero, we have:

0 = -16x^2 + 153x + 98

This is a quadratic equation that can be solved by factoring, completing the square, or using the quadratic formula. Once we find the values of x that make y equal to zero, we can determine the time, x, to the nearest 100th of a second.

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