Respuesta :
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They told us the total number of tickets sold and the worth of that total, we also know that there's 2 different types of tickets with different costs, adult tickets (let's call it, [tex]a[/tex]) pricing at $5, and student tickets (let's call it, [tex]s[/tex]) pricing at $1.
We can set up two equations, one for the number of tickets and he other for the worth of them:
[tex]a + u = 1288[/tex]
two different types of tickets which the sum of each type amounts to 1288.
[tex]5a+1u = 3260[/tex] or [tex]5a + u = 3260[/tex]
for 1 adult ticket is 5 bucks, for 1 student ticket is 1 buck and all of the purchased adult and student tickets amounts to be worth $3260
we can treat both equations like a system of equations!
hey! there's a [tex]u[/tex] in both equations, let's cancel (subtract) it!
[tex]5a + u = 3260[/tex]
-( [tex]a+u= 1288[/tex])
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4a = 1972
a = 493 (divide both sides by 4)
now let's plug that into one of the equations to find [tex]u[/tex]!
let's choose [tex]a+u=1288[/tex] because it's easier to solve:
493 + u = 1288
u = 795
WE DID IT!
493 ADULT TICKETS AND 795 STUDENT TICKETS WERE SOLD AT THE GAME!!!!!
( wow that's alot of people )
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