Respuesta :
final velocity = initial
velocity + (acceleration x time)
3.9 m/s = 0 m/s + (acceleration x 0.11 s)
3.9 m/s / 0.11 s = acceleration
30.45 m/s^2 = acceleration
distance = (initial velocity x time) +
1/2(acceleration)(time^2)
distance (0 m/s x 0.11 s) + 1/2(30.45 m/s^2)(0.11s ^2)
distance = 0.18 m
Answer:
(a). The acceleration is 35.5 m/s².
(b). The distance is 0.214 m.
Explanation:
Given that,
Speed = 3.9 m/s
Time = 0.11 s
We need to calculate the acceleration
Using formula of acceleration
[tex]a = \dfrac{v_{f}-v_{i}}{t}[/tex]
Put the value into the formula
[tex]a =\dfrac{3.9-0}{0.11}[/tex]
[tex]a=35.5\ m/s^2[/tex]
We need to calculate the distance
Using equation of motion
[tex]s = ut+\dfrac{1}{2}at^2[/tex]
Put the value in the equation
[tex]s =0+\dfrac{1}{2}\times35.5\times(0.11)^2[/tex]
[tex]s=0.214\ m[/tex]
Hence, (a). The acceleration is 35.5 m/s².
(b). The distance is 0.214 m.
