Which statements are true about the fully simplified product of (b – 2c)(–3b + c)? Check all that apply. The simplified product has 2 terms. The simplified product has 4 terms. The simplified product has a degree of 2. The simplified product has a degree of 3. The simplified product has a degree of 4. The simplified product, in standard form, has exactly 2 negative terms.

Respuesta :

Answer:

The simplified product has a degree of 2.

The simplified product, in standard form has exactly 2 negative terms.

Step-by-step explanation:

[tex](b - 2c)(-3b + c)[/tex]

LEts multiply it using FOIL method

[tex]b* -3b= -3b^2[/tex]

[tex]b*c= bc[/tex]

[tex](-2c) * (-3b)= 6bc[/tex]

[tex](-2c) * c= -2c^2[/tex]

The product is [tex]-3b^2 +bc+6bc-2c^2[/tex]

[tex]-3b^2+7bc-2c^2[/tex]

The simplified product has a degree of 2.

It has two negative terms

Answer: The correct options are,

The simplified product has a degree of 2,

The simplified product, in standard form, has exactly 2 negative terms.

Step-by-step explanation:

Here, the given expression,

[tex](b-2c)(-3b+c)[/tex]

By distributive property,

[tex]=(b-2c)(-3b)+(b-2c)(c)[/tex]

Again by distributive property,

[tex]=b(-3b)-2c(-3b)+bc-2c(c)[/tex]

[tex]=-3b^2+6bc+bc-2c^2[/tex]

[tex]=-3b^2+7bc-2c^2[/tex]

Which is the simplified form of the given expression,

That having three terms in which two terms are negative and the degree ( The highest sum of the exponents of the variables) is 2,

Hence, the correct options are,

The simplified product has a degree of 2,

The simplified product, in standard form, has exactly 2 negative terms.