The kinetic energy of the car when it reaches the bottom of the hill is about A. 0.466 J
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Further explanation
Let's recall Kinetic Energy Formula as follows:
[tex]\large {\boxed{Ek = \frac{1}{2}mv^2} }[/tex]
Ek = Kinetic Energy ( Joule )
m = mass of the object ( kg )
v = speed of the object ( m/s )
Let us now tackle the problem !
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Given:
mass of the car = m = 0.05 kg
initial speed of toy car = u = 0 m/s
initial height position of the car = h₁ = 0.95 m
final height position of the car = h₂ = 0 m
gravitational acceleration = g = 9.81 m/s²
Asked:
final kinetic energy of the car = Ek₂ = ?
Solution:
We will use Conservation of Energy to solve this problem:
[tex]Ep_1 + Ek_1 = Ep_2 + Ek_2[/tex]
[tex]mgh_1 + \frac{1}{2} m u^2 = mgh_2 + Ek_2[/tex]
[tex]mgh_1 + \frac{1}{2} m (0)^2 = mg(0) + Ek_2[/tex]
[tex]mgh_1 = Ek_2[/tex]
[tex]Ek_2 = 0.05 \times 9.81 \times 0.95[/tex]
[tex]Ek_2 \approx 0.466 \texttt{ J}[/tex]
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Learn more
- Impacts of Gravity : https://brainly.com/question/5330244
- Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454
- The Acceleration Due To Gravity : https://brainly.com/question/4189441
- Newton's Law of Motion: https://brainly.com/question/10431582
- Example of Newton's Law: https://brainly.com/question/498822
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Answer details
Grade: High School
Subject: Physics
Chapter: Energy
