For the first one, f(x) clearly has positive y values, while g(x) doesn't (from what I see). In addition, cos(x) has a range of [-1, 1] so 2cosx would have a range of [-2, 2] and 2cosx+1 would therefore have a range of [-3, 3]. In addition, the maximum of the graph shown is 3, so the answer would be f(x) and h(x)
For the second one, sin(x) (including any x value)has a range of [-1, 1] so 2sinx would have a range from [-2, 2] and the range for 2sinx-2 would be
[-4, -2] with the minimum being -4. For g(x), squaring something makes it positive, meaning that the minimum of (x-3)^2 would be 0. 0-1 would be -1. For h(x), the lowest is clearly -6, and -6 is lower than both -1 and -4, mking h(x) the smallest
