Answer :
[tex] a^{2}+ b^{2} = c^{2} [/tex] that is, hypotenuse.
Therefore, let the length of the hypotenuse be 'x.'
[tex] 25^{2}+ 60^{2}= x^{2} [/tex]
625+3600=[tex] x^{2} [/tex]
4225=[tex] x^{2} [/tex]
Therefore,
[tex] \sqrt{4225} [/tex]=x
65=x
The length of the hypotenuse is B.65 centimetres.
Therefore, let the length of the hypotenuse be 'x.'
[tex] 25^{2}+ 60^{2}= x^{2} [/tex]
625+3600=[tex] x^{2} [/tex]
4225=[tex] x^{2} [/tex]
Therefore,
[tex] \sqrt{4225} [/tex]=x
65=x
The length of the hypotenuse is B.65 centimetres.
