Answer with explanation:
We are given a piece-wise function f(x) as:
f(x)= 2x-1 when x<0
0 when x=0
and -2x+1 when x>0
- Clearly from the function we see that when x<0
we have a graph of the function as a straight line with positive slope, this means that the line is increasing in the interval (-∞,0)
and also at (0,-1) there will be a open circle
since when x→0- then f(0)→2×0-1= -1
The value of the function is 0
Hence, we get the point (0,0)
we get the graph as a decreasing line since the slope of the line is negative i.e. -2.
and the graph starts with open circle at (0,1)
since x→0+ we have: f(0)→1
The correct graph is attached to the answer.
