Answer :
Hi Kally
Here is what I was able to come up!
4/x-2/x^2y^3
Double check it ok...
Here is what I was able to come up!
4/x-2/x^2y^3
Double check it ok...
[tex]\frac{4y}{xy}-\frac{2x}{xy^3}=\frac{4}{x}-\frac{2}{y^3}\\\\\\\frac{4y}{xy}-\frac{2x}{xy^3}=\frac{4y^3}{xy^3}-\frac{2x}{xy^3}=\frac{4y^3-2x}{xy^3}[/tex]
