The demand equation for soccer tournament T-shirts is xy − 5,000 = y where y is the number of T-shirts the Enormous State University soccer team can sell at a price of $x per shirt. Find dy dx x = 6 . dy/dx x = 6 = T-shirts per dollar Interpret the result. When the price is set at $6, the demand is by T-shirts per $1 increase in price.

Respuesta :

The given equation is:

x y – 5000 = y

Rewrite this to create an explicit equation:

x y – y = 5000

y ( x – 1) = 5000

y = 5000 / (x – 1)

Derive to get dy / dx:

dy = - 5000 dx / (x – 1)^2

dy / dx = - 5000 / (x – 1)^2

 

So plugging in x = 6,

dy / dx = - 5000 / (6 – 1)^2

dy / dx = - 200

Answer:

[tex]\frac{dy}{dx}|_{x=6}= -200[/tex]

Step-by-step explanation:

Given : Demand equation [tex]xy − 5,000 = y[/tex]

To Find [tex]\frac{dy}{dx}|_{x=6}[/tex]

Solution :

[tex]xy- y= 5000[/tex]

[tex]y(x-1)= 5000[/tex]

[tex]y= \frac{5000}{x-1}[/tex]

Differentiating with respect to x

[tex]\frac{dy}{dx}= \frac{-5000}{(x-1)^2}[/tex]

Now substitute x = 6

[tex]\frac{dy}{dx}|_{x=6}= \frac{-5000}{(6-1)^2}[/tex]

[tex]\frac{dy}{dx}|_{x=6}= \frac{-5000}{5^2}[/tex]

[tex]\frac{dy}{dx}|_{x=6}= \frac{-5000}{25}[/tex]

[tex]\frac{dy}{dx}|_{x=6}= -200[/tex]

Hence [tex]\frac{dy}{dx}|_{x=6}= -200[/tex]  =T-shirts per dollar